- #1

- 42

- 0

a^2+b^2=25 and a^3+b^3=91. find the value of a and b.

Now here we cannot take that into consoderation that as a^2+b^2=25 , a=3 and b=4. But we have to find the answer without any assumtions.May i please get the answer as soon as possible

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter Milind_shyani
- Start date

- #1

- 42

- 0

a^2+b^2=25 and a^3+b^3=91. find the value of a and b.

Now here we cannot take that into consoderation that as a^2+b^2=25 , a=3 and b=4. But we have to find the answer without any assumtions.May i please get the answer as soon as possible

- #2

- 13,147

- 708

Daniel.

P.S. This is NOT "Advanced Physics".

- #3

- 335

- 0

a^3 + b^3 = (a+b)(25-ab)

Put a + b = x.

Then ab = [(a+b)^2 - (a^2 + b^2)]/2 = (x^2 - 25)/2

- #4

- 13,147

- 708

That's why i asked about the set in which you want to determine the solutions...

Daniel.

- #5

Physics Monkey

Science Advisor

Homework Helper

- 1,363

- 34

- #6

VietDao29

Homework Helper

- 1,424

- 3

Why do I hate people who double post so much!!! :grumpy: :grumpy: :grumpy:Milind_shyani said:

a^2+b^2=25 and a^3+b^3=91. find the value of a and b.

Now here we cannot take that into consoderation that as a^2+b^2=25 , a=3 and b=4. But we have to find the answer without any assumtions.May i please get the answer as soon as possible

Why must you post one problem in

Maths factorization problem!!!

In fact, it can be reduced to a cubic equation. :)dextercioby said:

That's why i asked about the set in which you want to determine the solutions...

Daniel.

Last edited:

Share: